An erect image 3 times the size of the object is obtained with a concave mirror of radius of curvature 36 cm.find the position of the object
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Given,
R=36 cm
or f=-36/2=-18 cm (It is a concave mirror)
magnification, m=h' /h=3=-v/u
or v=-3u
Now, using the mirror formula,
1/f=1/v + 1/u
-1/18=-1/3u + 1/u
or Object distance, u=-12 cm
R=36 cm
or f=-36/2=-18 cm (It is a concave mirror)
magnification, m=h' /h=3=-v/u
or v=-3u
Now, using the mirror formula,
1/f=1/v + 1/u
-1/18=-1/3u + 1/u
or Object distance, u=-12 cm
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