Question

An erect image 3times the size of the object is obtained with a concave mirror of radius of curvature 36cm.what is the position of the object ?full solution step by step​

Answer 1

Answer:

magnification m = - v/u = h'/h = +3

v = -3 u actually u is negative. Hence v is positive.

R = -36 cm => f = R/2 = -18 cm , negative for a concave mirror.

1/v + 1/u = 1/f, mirror equation

1/(-3u) + 1/u = 1/(-18)

2/(3u) = -1/18

u = - 12 cm v = +36 cm

the object is placed 12 cm from pole of concave mirror , less than the focal length, to have an ERECT magnified image 3 times the object.

Answer 2

Answer:

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