an erect image formed by a spherical mirror is half the size of object and formed at a distance of 10 cm behind it...find where the screen should be placed to obtain magnification of 1/3 of size of object
plz its my humble request that any of you plz answer this question
it's for 45 points
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Since the image is erect , so the magnification ratio must be positive .
m=2
also u=−10cm
so m=−
u
v
2=−
−10
v
v=20cm
So the image is virtual and 20 cm from mirror on the other side of the object
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