Question

an errect and 2.5 times magnified image is produced by a converging lens of focal length 10cm. Find the positions of the object and the image ​

Answer 1

Answer:

Since the image is erect , so the magnification ratio must be positive .

m=2

also u=−10cm

so m=−

u

v

2=−

−10

v

v=20cm

So the image is virtual and 20 cm from mirror on the other side of the object.

Explanation:

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