Chemistry, asked by GaneshTetakala1191, 10 months ago

An ester (A) with molecular fomula, C₉H₁₀O₂ was treated
with excess of CH₃MgBr and the complex so formed was
treated with H₂SO₄ to give an olefin (B). Ozonolysis of (B)
gave a ketone with molecular formula C₈H₈O which shows
positive iodoform test. The structure of (A) is
(a) C₆H₅COOC₂H₅
(b) C₂H₅COOC₆H₅
(c) H₃COCH₂COC₆H₅
(d) p—H₃CO—C₆H₄ —COCH₃

Answers

Answered by Fatimakincsem
0

The structure of A is C₆H₅COOC₂H₅.

Option (A) is correct.

Explanation:        

                                                                           OH

                                                                               |

C6 H5 COOC2H 5  + CH3 MgBr   ----------> C6 H5  −   C − CH3 +   H2 SO4  / Δ  

                                                                               |

                       CH3                                               CH3      O

                         |                                                                  ||

-----> C  6   H  5  −  C  = CH2   +  O 3  ----->   HCHO +  C  6  H  5  −  C  −CH3  ↓NaOI  

​ C6H5CONa  + CH3I

Thus the structure of A is C₆H₅COOC₂H₅.

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