Chemistry, asked by amannarang4990, 1 year ago

An ether [a], c5h12o, when heated with excess of hot concentrated hi produced two alkyl halides which when treated with naoh yielded compounds [b] and [c]. Oxidation of [b] and [c] gave a propanone and an ethanoic acid respectively. The iupac name of the ether [a] is:
a.2-ethoxypropane
b.Ethoxypropane
c.Methoxybutane
d.2-methoxybutane

Answers

Answered by Anonymous
4

The IUPAC name of the ether [a] is 2-ethoxypropane .

  • Propanone is formed due to oxidation of 2- Propanol . Hence [b] is 2- Propanol .
  • Ethanoic acid is formed due to oxidation of ethanol . Hence [c] is ethanol .
  • Thus the two alkyl halides must be 2- propyl halide and ethyl halide .
  • Hence , the ether is [a] 2-ethoxypropane .
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