Question

An event A and B are mutually exclusive with P(A)=0.3, P(B)=0.4 , then P(A/B)=...​

Answer 1

Answer:

P(AuB)= p(A) + p(B) - p(AnB)

Since P(A) and P(B) are independent, the intersection is the product of their individual probabilities (p(A)*p(B)).

We then have P(AuB) =0.3 + 0.4 - 0.3*0.4= 0.58