Question

an event is getting at the most one tail when two coins are tossed complete the activity to find the probability of the following events.

Answer 1

S=(HH,HT,TH,TT)

EVENT A =(HH,HT,TH)

P(A)= 3/4

Answer 2

Answer:

S= {HH, HT, TH, TT } :–n (S) = 4

A: Getting at the most one tail.

:– A ={HH, HT, TH} :– n(A) =3

P(A) = n(A)\n(S)

P(A) = [3\4] .