An examination consists of 25 questions. for each correct answer a student earns 4 marks and for each wrong answer, the student losses 1 mark. find the number of distinct net scores that a student could earn in that examination.
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Let the correct ans. be x. and, the wrong be y. x + y =25 ............(1) (x + 4) - (y - 1) = 25 ........(2) So, By Elimination Method, x + y =25 (x + 4) - (y - 1) = 25 So, x = 47 -------- 2 Now, by substituting value of x in any equation you can get y.... Hope it will help you...
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