An examination was held in two parts of the 630 examiners, 3/10 appeared in only the farst part and 2/15 appeared in only the second part the rest appeared in both the parts. find the number of examineees. who appeared in both the parts.
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Examiners appeared in first part only=3/10*630
=189
Examiners appeared only in second part =2/15*630=84
Thus examiners appeared in both=630-(189+84)=630-273=357...
Hope this helps you....
=189
Examiners appeared only in second part =2/15*630=84
Thus examiners appeared in both=630-(189+84)=630-273=357...
Hope this helps you....
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