Math, asked by sirishavulluri3251, 1 year ago

An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd work week was increased by 20% and increased by 16% in the 3rd work week but decreased by 20% in the 4th work week. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week indiabix

Answers

Answered by acesolution2017
2

Answer:


Step-by-step explanation:

Suppose there are x number of tickets were sold in first week;

Second week it is increase by 20%

Means total number of tickets sold in 2nd week is=x+(20/100)x=1.2x;

Now third week number of tickets increase by 16%

So total tickets sold on 3rd week is=1.2x+(16/100)1.2x=1.2x+0.192x=1.392x;

Now third week tickets were decrease by 20%

That is 1.392x-(20/100)(1.392x)=1.392x-0.2784x=1.1136x

Last week total number of tickets sold =1.1136x=1392

x=1250 (By solving)

1250 number of tickets in the beginning.


Answered by Anonymous
4
Hey mate ^_^

=======
Answer:
=======

Let initially 'x' ticket has been sold.

So,

In second week 20% increases.

So,

= x \times \frac{120}{100}

In third week 16% increases.

So,

= x \times ( \frac{120}{100} ) \times ( \frac{116}{100} )

In forth week 20% decrease.

So,

x \times ( \frac{120}{100} ) \times ( \frac{116}{100} ) \times ( \frac{80}{100} ) = 1392

x = 1250

Therefore,

Answer: 1250

#Be Brainly❤️
Similar questions