Question

An experiment consists of four outcomes with p(e1) = 0.2, p(e2) = 0.3, and p(e3) = 0.4. The probability of outcome e4 is

Answer 1

Answer:

.1

Step-by-step explanation:

i hope all outcomes are independent of each other.

probability of an outcome is 1

p1+p2+p3+p4 is 1

now 1-.2+.3+.4 is .1

.1 is your answer

Answer 2

The probability of outcome $e_4$ is 0.1.

Step-by-step explanation:

Given : An experiment consists of four outcomes with $p(e_1) = 0.2$, $p(e_2) = 0.3$, and $p(e_3) = 0.4$.

To find : The probability of outcome $e_4$ is ?

Solution :

We know the sum of all probabilities of an event is always 1.

$p(e_1) = 0.2$, $p(e_2) = 0.3$, and $p(e_3) = 0.4$.

So, $p(e_1)+p(e_2)+p(e_3)+p(e_4)=1$

$0.2+0.3+0.4+p(e_4)=1$

$0.9+p(e_4)=1$

$p(e_4)=1-0.9$

$p(e_4)=0.1$

The probability of outcome $e_4$ is 0.1.

#Learn more

An experiment consists of four tosses of a coin. Denoting the outcomes HHTH, THTT, ….and assuming that all 16 outcomes are equally likely, find the probability distribution for the total number of heads.

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