Question

An experiment is being performed to calculate the acceleration due to gravity using a pendulum. The below relation holds g = 4\pi ^2 \frac{L}{T^2}g=4π 2 T 2 L ​ The length of the pendulum is given as 1 m ± 5 cm The time is measured using a watch of Least count 1 second. The time for 20 oscillation is measured to be 40 s. Assume there is no other error in the measurement of this time. Calculate the final value of the acceleration due to gravity with appropriate errors.

Answer 1

Answer:

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Explanation:

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