Question

An experiment is set up as shown. Flasks 1 and 2 contain lime water. Air is pumped through the flasks. What is the appearance of lime water in flasks 1 and 2 after a period of ten minutes?

flask 1/ flask 2 - clear/clear

flask 1/ flask 2 - clear/white, cloudy

flask 1/ flask 2 - white, cloudy/ clear

flask 1/ flask 2 - white, cloudy/white, cloudy

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Answer 1

Answer:

Lime water turns milky in the presence of CO2. In flask-1, the air containing CO2 enters into the flask, but due to the presence of KOH all the CO2 gets absorbed by it. So, there will be no change in the lime water.

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Answer 2

Option B : Flask 1 remains clear due to the presence of Potassium Hydroxide. And Flask 2 becomes white and cloudy due to the formation of Calcium Carbonate.

Lime Water reaction with Carbon dioxide :

• The chemical name for lime water is Calcium Hydroxide
• In the reaction of calcium hydroxide i.e. lime water with carbon dioxide, a compound called calcium carbonate is formed which is milky and cloudy white in appearance.

Experiment Reactions and Formations :

• Here, the container in the middle has living organisms which breathe and thus release carbon dioxide i.e. $CO_{2}$
• The flask 1 and 2 have Lime water in them i.e. $Ca(OH)_{2}$
• The additional tube on the left attached to Flask 1 has Potassium Hydroxide i.e. $KOH$ which is a good absorber of carbon dioxide.

In Flask 2, the Lime water in it and the carbon dioxide received from the living animal's container react to form a milky white solid substance i.e. calcium carbonate. The according reaction is :

                   $Ca(OH)_{2}(aq) + CO_{2}(g)$   ⇒  $CaCO_{3} (s) + H_{2}O(l)$

But in Flask 1, the carbon dioxide released by the living creatures is immediately captured and absorbed by the Potassium Hydroxide solution attached. Thus, the carbon dioxide is not available to react with the lime water and produce the white milky precipitate. Thus, the solution in flas1 remains clear as it was originally.

                        $KOH + CO_{2}$  ⇒ $K_{2}CO_{3} +H_{2}O$

Hence, Flask 1 has a clear solution and the Flask 2 has milky, cloudy white precipitate due to formation of calcium carbonate after a period of 10 minutes.

To learn more about Lime Water, visit

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