An experiment succeeds twice as often as it fails.The chance thatg in next six trails there shall be at least 4 success is ?
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let probablity of sucess = p
and that of failure = q
given A/Q ⇒ p =2q and aslo p+q = 1
that gives p = 2/3 and q = 1/3
now question asking at least 4 success ⇒ P(n=4) + P( n =5) + P(n=6)
P(n=x) = ⁿCₓ (p)ˣ (q)ⁿ⁻ˣ here n= 6
so ans = ⁶C₄ (2/3)⁴ (1/3)² + ⁶C₅(2/3)⁵(1/3)¹ + ⁶C₆(2/3)⁶(1/3)⁰
= 15. 16/81. 1/9 + 6 . 32/243 . 1/3 + 1. 64/729 .1 = 493/729
hope that correct ans = c) 496/729
and that of failure = q
given A/Q ⇒ p =2q and aslo p+q = 1
that gives p = 2/3 and q = 1/3
now question asking at least 4 success ⇒ P(n=4) + P( n =5) + P(n=6)
P(n=x) = ⁿCₓ (p)ˣ (q)ⁿ⁻ˣ here n= 6
so ans = ⁶C₄ (2/3)⁴ (1/3)² + ⁶C₅(2/3)⁵(1/3)¹ + ⁶C₆(2/3)⁶(1/3)⁰
= 15. 16/81. 1/9 + 6 . 32/243 . 1/3 + 1. 64/729 .1 = 493/729
hope that correct ans = c) 496/729
parisakura98pari:
do u get the ans?
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