Question

an experiment with the common balance the mass of a ring is found to be 2.52g,2.53g,2.51g,2.49g and 2.54g.calculate mean value of the mass of the ring, absolute error, mean absolute error, relative and % error

Answer 1

Answer:

◆ Answer -

m = 2.518 g

◆ Explanation -

# Given -

m1 = 2.52 g

m2 = 2.53 g

m3 = 2.51 g

m4 = 2.49 g

m5 = 2.54 g

# Solution -

Mean value of mass of the ring will be given by -

m = (m1 + m2 + m3 + m4 + m5) / 5

m = (2.52 + 2.53 + 2.51 + 2.49 + 2.54) / 5

m = 12.59 / 5

m = 2.518 g

Therefore, mean mass of the ring will be 2.518 g.

Answer 2

Answer:

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