Question

an experiment with the common balance the mass of a ring is found to be 2.52g,2.53g,2.51g,2.49g and 2.54g.calculate ablosute error

Answer 1

Mean value of mass of the ring will be given by -

m = (m1 + m2 + m3 + m4 + m5) / 5

m = (2.52 + 2.53 + 2.51 + 2.49 + 2.54) / 5

m = 12.59 / 5

m = 2.518 g

Therefore, mean mass of the ring will be 2.518 g.

Answer 2

Answer:

average = 12.59/5

= 2.518

then absolute error of 2.52 is = 2.52-2.518 = 0.002

then of 2.53 = 0.012

then of 2.51 = -0.008

then of 2.49 = -0.028

then of 2.54= 0.022