Question

. An experimental arrangement for measuring the thermal conductivity of solid materials involves the use of two long rods that are equivalent in every respect, except that one is fabricated from a standard material of known thermal conductivity kA while the other is fabricated from the material whose thermal conductivity kB is desired. Both rods are attached at one end to a heat source of fixed temperature Tb, are exposed to a fluid of temperature T(, and are instrumented with thermocouples to measure the temperature at a fixed distance x1 from the heat source. If the standard material is aluminum, with kA = 200 W/m(K, and measurements reveal values of TA = 75oC and TB = 60oC at x1 for Tb = 100oC and T( = 25oC, what is the thermal conductivity kB of the test material?

Answer 1

Answer:

given ,

the two rods could be approximitad as a fine infinite length

TA = 75 o c OA = ( TA - TOO )= 75 - 25 = 50 o c

TB = 60 o c o b = ( Tb - Too ) = 60 - 25 = 35 o c

Tb = 100 o c o b = ( Tb - Too ) = ( 100 - 25 ) = 75 o c

Explanation:

hope it it will help you

please mark me as a BRAIN LIST FRIENDS

Answer 2

Answer:56.60 W/m K

For a keeping all other parameters constant the ratio of m1/m2 becomes ratio of root of thermal conductivity.

See the solution in the below attached image.