Question

. An explorer travels 5 Km due south. He then travels 6 Km on a bearing of 100°
.
He then wishes to go straight back to where he started from.
(a) Calculate the distance he will have to travel.

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

In ΔAOB,O is right angle.

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB)

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2 =(OB)

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2 =(OB) 2

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2 =(OB) 2 +(OA)

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2 =(OB) 2 +(OA) 2

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2 =(OB) 2 +(OA) 2

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2 =(OB) 2 +(OA) 2 =9+16

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2 =(OB) 2 +(OA) 2 =9+16(AB)

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2 =(OB) 2 +(OA) 2 =9+16(AB) 2

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2 =(OB) 2 +(OA) 2 =9+16(AB) 2 =25

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2 =(OB) 2 +(OA) 2 =9+16(AB) 2 =25AB=5

In ΔAOB,O is right angle.∴ Applying Pythogorus theorem,(AB) 2 =(OB) 2 +(OA) 2 =9+16(AB) 2 =25AB=5∴ He is 5km from starting point.