Question

An express train take one hour less than a passenger train to tavel 132km between bangalore and mysur if express train speed is 1km mpre than passenger train find out average speed of the two train

Answer 1

speed of passenger train be x
speed of express train be (x+11)
132/x - 132/(x+11) = 1
132[x+11-x/x(x+11)] = 1
132×11 = x(x+11)
x^2 + 11x - 1452 = 0
(x-33)(x+44)
x=33

Answer 2

❤Hereis your solutions❤

Let speed of passenger train is x km/hr.

speed of express train= (x+11) km/hr.

Time taken by the passenger train= 132 / x hrs.

Time taken by the express train= 132/ (x+11) hrs.

a/q

(132/x) - (132/ x+11)= 1

132(x+11) -132(x) / x(x+11)=1

=> 132x+1452- 132x / x(x+11)=1

=> x^2+11x-1452= 0

=> x^2+44x-33x-1452= 0

=> x(x+44) -33(x+44)=0

=> (x-33) (x+44)=0

=> x=33 or x = -44

we take x = 33 (positive )

Therefore,

speed of passenger train= x km/hr= 33 km/ hr

speed of express train= (x+11) km/hr= 33+11 =44km/hr.