An express train taken 1hour less than a passenger train to travel 132km between mysore and bangalore. If th average speed of the express train 11km / h more than that of the passenger train find the average spreed of the 2 train
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❤Hereis your solutions❤
Let speed of passenger train is x km/hr.
speed of express train= (x+11) km/hr.
Time taken by the passenger train= 132 / x hrs.
Time taken by the express train= 132/ (x+11) hrs.
a/q
(132/x) - (132/ x+11)= 1
132(x+11) -132(x) / x(x+11)=1
=> 132x+1452- 132x / x(x+11)=1
=> x^2+11x-1452= 0
=> x^2+44x-33x-1452= 0
=> x(x+44) -33(x+44)=0
=> (x-33) (x+44)=0
=> x=33 or x = -44
we take x = 33 (positive )
Therefore,
speed of passenger train= x km/hr= 33 km/ hr
speed of express train= (x+11) km/hr= 33+11 =44km/hr.
Let speed of passenger train is x km/hr.
speed of express train= (x+11) km/hr.
Time taken by the passenger train= 132 / x hrs.
Time taken by the express train= 132/ (x+11) hrs.
a/q
(132/x) - (132/ x+11)= 1
132(x+11) -132(x) / x(x+11)=1
=> 132x+1452- 132x / x(x+11)=1
=> x^2+11x-1452= 0
=> x^2+44x-33x-1452= 0
=> x(x+44) -33(x+44)=0
=> (x-33) (x+44)=0
=> x=33 or x = -44
we take x = 33 (positive )
Therefore,
speed of passenger train= x km/hr= 33 km/ hr
speed of express train= (x+11) km/hr= 33+11 =44km/hr.
smartyAnushka:
Nice...❤
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