An Express train takes 1 hour less than a passenger train to travel 132 km between Mysore and Bangalore. If average speed of the express train is 11 km per hour none than that of the passenger train. Find the average speed of two trains
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let speed of pasenger train be = x km
speed of express train be = x + 11 km
time = distance / speed
A.T.Q,
132/X+11 - 132/X = 1
132x -132x + 1452 / (X) (X + 11)= 1
1452 =x^2 + 11x
x^2+11x-1452=0
x^2+44x -33x -1452=0
x (x+44) -33(x+44)=0
(x+44) (x-33) =0
x = -44 and 33
neglecting -44 as speed can't be negative.
speed of passanger train =33km/hr. Ans.
speed of express train = x+11
= 33+11
= 44 km / hr.Ans..
plxzzz mark it as brainlieast answer if helpful....
speed of express train be = x + 11 km
time = distance / speed
A.T.Q,
132/X+11 - 132/X = 1
132x -132x + 1452 / (X) (X + 11)= 1
1452 =x^2 + 11x
x^2+11x-1452=0
x^2+44x -33x -1452=0
x (x+44) -33(x+44)=0
(x+44) (x-33) =0
x = -44 and 33
neglecting -44 as speed can't be negative.
speed of passanger train =33km/hr. Ans.
speed of express train = x+11
= 33+11
= 44 km / hr.Ans..
plxzzz mark it as brainlieast answer if helpful....
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