Question

An express train takes 1 hour less than a passenger train to travel 132 km/hr between Mysore and Bangalore.If the average speed of the express train is 11 km/hr more than that of passenger train,form an equation to find the average speed of the express train.

Answer 1

Heya !!

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Let the speed of the express train be x km/hr.

So, the speed of passenger train = (x–11) km/hr

Total distance to be covered = 132 km

A.T.Q.

132/(x–11) – 132/x = 1

=> 132x–132x+1452 = x²–11

=> x²–11x–1452 = 0

=> x²–44x+33x–1452 = 0

=> x(x–44) + 33(x–44) = 0

=> (x+33) (x–44) = 0

=> x = –33 or x = 44

Since, speed can't be negative.
So, x = –33 is inappropriate.

Therefore, speed of express train is 44 km/hr and speed of passenger train is (44–11) km/hr i.e., 33 km/hr

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Hopr my ans.'s satisfactory.☺