Question

an Express train takes 1 hour less than a passenger train to travel 132 kilometre between Mysore and Bangalore if the average speed of the express train is 11 km per hour more than that of the passenger train from the quadratic equation to find the average speed of Express train

Answer 1

Hey user here is your answer.......

----> Speed of passenger train be x km/hr
◆Speed of express train = (x+11)

◆Total distance =132km
◆Speed=distance/time

◆Time taken by passenger train=132/x hr.

◆Time taken by express train=132/(x+11)


●According to question

◆132/x -132/(x+11)=1

◆132(1/x-1/x+11)=1

◆132(x+11-x/x^2+11x)=1

◆132(11/x^2+11x)=1

◆1452/x^2+11x=1

◆x^2+11x-1452=0

◆By middle term splitting

◆ x^2+44x-33x-1452=0

◆x(x+44)-33(x+44)=0

◆(x-33)(x+44)=0

◆x-33=0

&

◆x+44=0

Speed can't be in negative

So,

◆Hence speed of passenger train is 33 km/hr

◆Speed of express train =(x+11)
=44km/hr

Hope it helps you☺️

Regards
#Rohan ( Maths aryabhatta)