Question

an Express train takes 1 hour less than a passenger train to travel 132 kilometre between Mysore and Bangalore if the average speed of the express train is 11 km or more than that of the passenger train ,form the quadratic equation to find the average speed of Express train.

Answer 1

Let the speed of passanger train =x
Let the speed of Express train=(x+11)

let the time taken by passanger train =132/x
let the time taken by express train =132/x+11

132/x - 132/x+11 = 1

Answer 2

☜☆☞hey Megha!!!!☜☆☞

Here is the answer to your question ☞
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Let the average speed of the passenger train be x km/hr

∴Average speed of the express train = (x + 11) km/hr

Given, Time taken by express train to travel 132 km = Time taken by passenger train to travel 132 km – 1 hr


=> 132/(x+11) = 132/x - 1

=> 132/x - 132/(x+11) = 1

=> 132x+1452-132x/x(x+11) = 1

=> 1452 = x²+11x

=> x²+11x-1452 = 0 ______answer

thus, the quadratic equation representing the given information is "x²+11x-1452=0"



I think my answer is capable to clear your confusion

Devil_king ▄︻̷̿┻̿═━一