Question

an Express train takes 1 hour less than a passenger train to travel 132 km between two station if the average speed of the express train in 11 km per hour more than the passenger train then find the average speed of two trains..
plzzz answer me quickly...

Answer 1

HEY FRIEND HERE YOUR ANSWER

Let the speed of passenger train be x km/hr

Hence speed of express train = (x +11) km/hr

Distance travelled by both the trains = 132 km

Time taken = (Distance)/(Speed)

Time taken by the passenger train = 132/x hrs

Time taken by the express train = 132/(x + 11) hrs

⇒�132 × 11 = x(x + 11)

⇒�x �+ 11x – 1452 = 0

⇒�x �+ 44x – 33x – 1452 = 0

⇒�x(x + 44) – 33(x + 44) = 0

⇒�(x + 44)(x – 33) = 0

⇒�(x + 44) = 0 or (x – 33) = 0

∴ x = –44 or x = 33 Since speed cannot be negative, x = 33 Thus the sped of passenger train is 33 km/hr and speed of express train is 44 km/hr.

I HOPE IT'S HELP YOU

MARK BRAINLIEST MY ANSWER DEAR FRIEND