an express train takes 1 hour less than passanger train to travel 132 km between mysor & Bangalore .if average speed of express train is 11 km / h more than that passenger train . find the average speed of two train
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let the average speed of express train be 'x' km/ h and the time taken by express train be 'x' hr.
for the passenger trains average speed=x- 11, taken =t+1 .
distance= speed ×time
given, total distance travelled= 132
x×t=132
t =132/ x
also, (x-11) ×(t+1) =132
(x-11) × ( 132/x +1)= 132
(x-11) (x+132) =132x
x^2 -11x +132x- 1452 =132 x
x^2 -11x -1452 =0
required quadratic equation
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for the passenger trains average speed=x- 11, taken =t+1 .
distance= speed ×time
given, total distance travelled= 132
x×t=132
t =132/ x
also, (x-11) ×(t+1) =132
(x-11) × ( 132/x +1)= 132
(x-11) (x+132) =132x
x^2 -11x +132x- 1452 =132 x
x^2 -11x -1452 =0
required quadratic equation
mark me brainiest
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