Question

an Express train takes 1 hour less than passenger train to travel 132 Mysore to Bangalore if the average speed of the express train is 11 km per hour more than that the passenger train from the quadratic equation to find the average speed of Express train ​

Answer 1

Answer:

passenger train=33km/hr

express train=44km/hr

Step-by-step explanation:

$passenger \: train \: = x \: \frac{km}{hr} \\ express \: train = (x + 11) \frac{km}{hr} \\ mysore \: to \: banglore = 132km \\ \frac{132}{(x + 11)} = \frac{132}{x} + 1 \\ \frac{132}{(x + 11)} = \frac{132 + x}{x} \\ 132x = (132 + x)(x + 11) \\ 132x = 132x + 1452 + {x}^{2} + 11x \\ {x}^{2} + 11x + 1452 = 0 \\ {x}^{2} + 44x - 33x - 1452 = 0 \\ x(x + 44) - 33(x + 44) = 0 \\ (x - 33)(x + 44) = 0 \\ x = 33 \: \: and \: - 44 \\ the \: speed \: of \: passenger \: train \: = 33 \frac{km}{hr} \\ speed \: of \: express \: train = 33 + 11 = 44 \frac{km}{hr}$