Question

An express train takes 1 hr less than passenger train to travel 132km . if average speed is 11 km / hr more than passenger train formulate an equation to find average speed of express train...​

Answer 1

Answer:

Let the speed of passenger train be x km/hr

Hence speed of express train = (x +11) km/hr

Distance travelled by both the trains = 132 km

Time taken = (Distance)/(Speed)

Time taken by the passenger train = 132/x hrs

Time taken by the express train = 132/(x + 11) hrs

⇒�132 × 11 = x(x + 11)

⇒�x2�+ 11x – 1452 = 0

⇒�x2�+ 44x – 33x – 1452 = 0

⇒�x(x + 44) – 33(x + 44) = 0

⇒�(x + 44)(x – 33) = 0

⇒�(x + 44) = 0 or (x – 33) = 0

∴ x = –44 or x = 33

Since speed cannot be negative, x = 33

Thus the sped of passenger train is 33 km/hr and speed of express train is 44 km/hr.

Answer 2

Answer:

The speed of passenger train is 33 km per hour nd the speed of express train is 44 km per hour !!!!

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