Question

An expression involving byte, int and literal numbers is promoted to
a) int
b) long
c) byte
d) float

Answer 1

Answer:

A) int is the correct answer all other are not

Answer 2

Answer:

a) int

An expression involving byte, int and literal numbers is promoted to int.

Explanation:

A byte, int, and literal number expression is promoted to an int expression. Before any calculations are performed, an expression made up of bytes, ints, shorts, and literal numbers is promoted to an int. Before any calculations are made, an expression made up of bytes, ints, shorts, and literal numbers is promoted to an int.

• A literal integer is always an int, but anything int-sized or less that is the result of an expression is also always an int. In other words, even if two bytes are very small, adding them together yields an int.
• You can create an int by multiplying an int by a short. An int is obtained by dividing a short by a byte.
• Every expression that contains bytes, ints, shorts, or literal numbers is promoted to an int before any calculations are made.
• When you widen a conversion, there is an implicit cast. Alternatively, packing a smaller object (like a byte) into a larger container (like an int).