An expression is shown below: 22(x^(4)-x^(3)-20x^(2)) Varun performed the first step to factorise the expression as shown below. 22x^(2)(x^(2)-x-20)
Answers
sorry I didn't get the question
Given : An expression is shown below: 22(x⁴-x³-20x²)
Varun performed the first step to factorise the expression as shown below. 22x²(x²-x-20)
To Find : Using which identity can Varun factorize the expression further?
Solution:
22(x⁴-x³-20x²)
Taking x² common
22x²(x²-x-20)
Next he can use middle term split method to factorize
He can write - x as sum of two expressions whose product
is -20x²
- x can be written as -5x + 4x
so
22x²(x²-5x + 4x-20)
= 22x² ( x( x- 5) + 4(x - 5))
= 22x² ( x- 5) (x + 4)
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