Question

An expression is shown below: · 22(x+-x-20x°) Varun performed the first step to factorise the expression as shown below. 22x²(x2-x-20) Using which identity can Varun factorise the expression further?​

Answer 1

Answer:

i don't know the answer

Step-by-step explanation:

but i try to answer ir

Answer 2

Given : An expression is shown below: 22(x⁴-x³-20x²)

Varun performed the first step to factorise the expression as shown below. 22x²(x²-x-20)​

To Find : Using which identity can Varun factorize the expression further?​

Solution:

22(x⁴-x³-20x²)

Taking x² common

22x²(x²-x-20)​

Next he can use middle term split method to factorize

He can write - x  as  sum of two  expressions whose product

is -20x²

- x can be written as  -5x + 4x

so

22x²(x²-5x + 4x-20)​

= 22x² ( x( x- 5) + 4(x - 5))

= 22x² ( x- 5) (x + 4)

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