An extended object of 5 cm is placed in front of a concave mirror of curvature 40 cm produces an image which is two times of an object find the position and height of the object
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Answer:
u=-30cm
Explanation:
f=R/2
f=-20cm
m=v/u
H/h=v/u
2=v/u
v=2u–––––1
1/v+1/u=1/f
1/2u+1/u=-1/20
1/u(1/2+1)=-1/20
1/u=-1/30
u=-30cm
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