Physics, asked by ansarskhan6289, 10 months ago

An extended object of 5 cm is placed in front of a concave mirror of curvature 40 cm produces an image which is two times of an object find the position and height of the object

Answers

Answered by sonasudhi4444
0

Answer:

u=-30cm

Explanation:

f=R/2

f=-20cm

m=v/u

H/h=v/u

2=v/u

v=2u–––––1

1/v+1/u=1/f

1/2u+1/u=-1/20

1/u(1/2+1)=-1/20

1/u=-1/30

u=-30cm

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