an exterior angle and the interior angle of a regular polygon Are in the ratio 3 and 6find the no. of sides of the polygon
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Let the interior angle of polygon P be A and exterior angle be B. And n be the number of sides of P.
given:
A/B=6/3
As we know
1. the interior angle A is 180(n−2)/n
2. the exterior angle B is 360/n
Thus,
180∗(n−2)/n divided by360/n =2
on simplifying. (n−2)/2=2
And n = 6 satisfies the given equation.
It's a hexagon.
given:
A/B=6/3
As we know
1. the interior angle A is 180(n−2)/n
2. the exterior angle B is 360/n
Thus,
180∗(n−2)/n divided by360/n =2
on simplifying. (n−2)/2=2
And n = 6 satisfies the given equation.
It's a hexagon.
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