An exterior angle is 104° and the interior opposite angles differ by 10°. Find all the angles of the triangle please solve this problem PLEASE
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Let one interior angle be x
Then the other will be x-10
And the final angle will be y
As the exterior angle is equal to the sum of the interior opposite angles,
104 = x + x - 10
2x - 10 = 104
2x = 114
x = 114/2
x = 57
x-10 = 47
Using ASP of a triangle
57 +47 + y = 180
104 + y = 180
y = 180 - 104
y = 76
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