An exterior angle of a cyclic quadrilateral is congruent to the angle opposite to its adjacent interior angle.
write the proof of the theorem yourself.
Answers
To prove
angle CBE = angle ADC
Proof
ABCD is a cyclic quadrilateral.
So
angle ABC+ angleADC = 180 (opp.angle of cyclic quadrilateral)
angle ABC+ angle CBE= 180( Linear pair)
from above
angle ABC+ angle ADC = angleABC + angle CBE
Or
angle ADC = angle CBE
here is your answer.
hope it may help you
Answer:
Step-by-step explanation:
To prove :
Let O be the centre of the circle. Join O to B and D. Then let the angle subtended by the minor arc and the major arc at the centre be xº and yº respectively.angle CBE = angle ADC
Proof :
ABCD is a cyclic quadrilateral.
So
angle ABC + angleADC = 180 ...(opp.angle of cyclic quadrilateral)
angle ABC+ angle CBE= 180 ...( Linear pair)
from above
angle ABC+ angle ADC = angleABC + angle CBE
Or
angle ADC = angle CBE
Hence proved