An exterior angle of a parallelogram is 110 . Find angles . I need verified answer
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Answered by
9
ZA = 110°
Step-by-step explanation:
ABCD is a parallelogram.
ZCBX is exterior angle of parallelogram
ABCD.
ZCB + ABC = 180° 110° + ZABC = 180°
= ZABC = 180° - 110°
ZABC = 70°
ZB = ZD
[.:. Opposite angles of parallelogram are
equal ]
so, ZD = 70°
ZDCB + ZABC = 180° [.. Supplementary angles ]
ZDCB + 70° = 180° ZDCB = 180° - 70°
ZDCB = 110° =
Now,
ZC = ZA
[.. Opposite angles of parallelogram are
equal ]
ZA = 110°
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Answered by
4
Answer:
Graphs of Inverse Trigonometric Functions
Function Domain Range
sin−1(x) [−1,1] [−π2,π2]
cos−1(x) [−1,1] [0,π]
tan−1(x) (−∞,∞) (−π2,π2)
cot−1(x) (−∞,∞) (0,π)
Step-by-step explanation:
ok
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