Question

An exterior angle of a parallelogram is 110 . Find angles . I need verified answer

Answer 1

ZA = 110°

Step-by-step explanation:

ABCD is a parallelogram.

ZCBX is exterior angle of parallelogram

ABCD.

ZCB + ABC = 180° 110° + ZABC = 180°

= ZABC = 180° - 110°

ZABC = 70°

ZB = ZD

[.:. Opposite angles of parallelogram are

equal ]

so, ZD = 70°

ZDCB + ZABC = 180° [.. Supplementary angles ]

ZDCB + 70° = 180° ZDCB = 180° - 70°

ZDCB = 110° =

Now,

ZC = ZA

[.. Opposite angles of parallelogram are

equal ]

ZA = 110°

Answer 2

Answer:

Graphs of Inverse Trigonometric Functions

Function Domain Range

sin−1(x) [−1,1] [−π2,π2]

cos−1(x) [−1,1] [0,π]

tan−1(x) (−∞,∞) (−π2,π2)

cot−1(x) (−∞,∞) (0,π)

Step-by-step explanation:

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