Question

An exterior angle of a parallelogram is 110°. Find the angles of the parallelogram.​

Answer 1

Answer:

Solution : ABCD is a parallelogram.

∠CBX is the exterior angle of the parallelogram.

∠CBX + ∠ABC = 180

110 + ∠ABC = 180

∠ABC = 180-110

∠ABC = 70

∠B = ∠D

{ OPPOSITE ANGLES OF A PARALLELOGRAM ARE EQUAL}

∠D = 70

∠DCB +∠ABC  = 180

{ SUPPLEMENTARY ANGLES}

∠DCB + 70 =180

∠DCB = 180-70 = 110

∠C = ∠A

∠A = 110

Step-by-step explanation:

Answer 2

1. angle A =110
2. angle B=70
3. angle C=110
4. angle D=70