Math, asked by gowrikumar777719, 10 months ago

An exterior angle of a regular polygon is one-fourth in each it's exterior angle. Find the number of sides of the Polygon​

Answers

Answered by Anonymous
2

Answer:

Let ext. Angle is x

X+4x=180/5

X=180/5

X=36

4x=36*4

=144

Ext. angle =360/n

n =360/36

n=10

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Answered by handsomeram16645
1

solution

Let ext. Angle is x

Let ext. Angle is xX+4x=180/5

Let ext. Angle is xX+4x=180/5X=180/5

Let ext. Angle is xX+4x=180/5X=180/5X=36

Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4

Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4=144

Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4=144Ext. angle =360/n

Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4=144Ext. angle =360/nn =360/36

Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4=144Ext. angle =360/nn =360/36n=10

Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4=144Ext. angle =360/nn =360/36n=10I think it will help you

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