An exterior angle of a regular polygon is one-fourth in each it's exterior angle. Find the number of sides of the Polygon
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Answer:
Let ext. Angle is x
X+4x=180/5
X=180/5
X=36
4x=36*4
=144
Ext. angle =360/n
n =360/36
n=10
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solution
Let ext. Angle is x
Let ext. Angle is xX+4x=180/5
Let ext. Angle is xX+4x=180/5X=180/5
Let ext. Angle is xX+4x=180/5X=180/5X=36
Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4
Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4=144
Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4=144Ext. angle =360/n
Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4=144Ext. angle =360/nn =360/36
Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4=144Ext. angle =360/nn =360/36n=10
Let ext. Angle is xX+4x=180/5X=180/5X=364x=36*4=144Ext. angle =360/nn =360/36n=10I think it will help you
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