an exterior angle of a triangle is 105 and its two interior opposite angles are equal then what is measure of these two equal angles?
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Answered by
101
In a triangle, the sum of two interior opposite angles is equal to the exterior angle.
=> For ∆ABC, exterior angle C = angle A + angle B
So in the question, we are given that the interior opposite angles are equal and the exterior angle to them is of 105°
Let the interior opposite angles be x
=> x + x = 105
=> 2x = 105
=> x = 105/2
=> x = 52.5°
So, the measure of these two angles is 52.5°
Answer :- 52.5°
Additional details :-
The third angle would form linear pair with the exterior, so third angle = 180 - 105 = 75°
=> For ∆ABC, exterior angle C = angle A + angle B
So in the question, we are given that the interior opposite angles are equal and the exterior angle to them is of 105°
Let the interior opposite angles be x
=> x + x = 105
=> 2x = 105
=> x = 105/2
=> x = 52.5°
So, the measure of these two angles is 52.5°
Answer :- 52.5°
Additional details :-
The third angle would form linear pair with the exterior, so third angle = 180 - 105 = 75°
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ayushdwivedipassion:
but in my book answer is stated as 37.5
Answered by
39
let angle x = angle y (givin)
105° + angle x = 180° ( linear pair)
angle x = 180°-105° = 75°
angle x = angle y (givin)
75° = angle y
angle x = 75°
angle y = 75°
I hope it will help you..
Thank you :-)
105° + angle x = 180° ( linear pair)
angle x = 180°-105° = 75°
angle x = angle y (givin)
75° = angle y
angle x = 75°
angle y = 75°
I hope it will help you..
Thank you :-)
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