An exterior angle of a triangle is 105°and it's two interior opposite angles are equal .Find each of these angle
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exterior angle of a triangle = sum of two interior opposite angles.
let interior angle be x . both are equal , so 2x
105= 2x
x= 105/2
= 52.5°
each
hope it helps you:-))))
let interior angle be x . both are equal , so 2x
105= 2x
x= 105/2
= 52.5°
each
hope it helps you:-))))
Answered by
20
Heya ✋
Let see your answer !!!!!
Given that
Exterior angle of a triangle = 105°
Two interior opposite angles are equal.
Solution
Let the interior opposite angles be x°. Then,
x + x = 105 [ sum of interior opposite angles]
=> 2x = 105
=> x = 105/2
=> x = 52.5
Hence , the angles are 52.5°.
Thanks :))))
Let see your answer !!!!!
Given that
Exterior angle of a triangle = 105°
Two interior opposite angles are equal.
Solution
Let the interior opposite angles be x°. Then,
x + x = 105 [ sum of interior opposite angles]
=> 2x = 105
=> x = 105/2
=> x = 52.5
Hence , the angles are 52.5°.
Thanks :))))
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