An exterior angle of a triangle is 105and its interior opposite angles are equal to each other. find the measure of each angle of triangle
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all its angles are 75°,75°,40°
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180°-105°=75° (using exterior angle theorem)
as the opposite angles are equal to each other,
then,
75°+75°+ vertex angle =180°(angle sum property of triangle)
vertex angle =30°
so angles of the triangle are
75°,75°,30°
as the opposite angles are equal to each other,
then,
75°+75°+ vertex angle =180°(angle sum property of triangle)
vertex angle =30°
so angles of the triangle are
75°,75°,30°
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