An exterior angle of a triangle is 105º and its two interior opposite angles are such that one angle is 1
greater than the other. Then angles are
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Answer:
An exterior angle of a triangle is 105 and its two interior opposite angles are equal. Each of these equal angles is:
EXTERIOR ANGLE OF THE TRIANGLE= 105 DEGREES
AND BOTH the Interior angles are equal..
let both the equal angles be x degree each
then ,
=> 105° = x°+x° ∵(exterior angle of a triangle is equal to the sum of interior opposite angles..)
∴ 105° = 2x°
105/2 = x°
therefore,
x° = 52.5°
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Given: Exterior angle = 105
∘
Let the two Interior angles be x.
Sum of Interior opposite angles = Exterior angle
x+x=105
2x=105
x=52.2∘
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