An exterior angle of a triangle is 110 ,and one of the interior opposite angle is 30.Find the other two angles of the triangle
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Let the other interior opposite angle= x
30 degrees+ x=110 degrees
x= 110 degrees - 30 degrees
x= 80 degrees
Therefore the other interior angle=80 degrees
To find the last angle we can apply the angle sum property----
The sum of all angles of a triangle = 180 degrees
Let the unknown angle= y
30 degrees+80 degrees+y=180 degrees
110 degrees+y=180 degrees
y=180 degrees- 110 degrees
y=70 degrees
Therefore the last angle=70 degrees
30 degrees+ x=110 degrees
x= 110 degrees - 30 degrees
x= 80 degrees
Therefore the other interior angle=80 degrees
To find the last angle we can apply the angle sum property----
The sum of all angles of a triangle = 180 degrees
Let the unknown angle= y
30 degrees+80 degrees+y=180 degrees
110 degrees+y=180 degrees
y=180 degrees- 110 degrees
y=70 degrees
Therefore the last angle=70 degrees
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