An exterior angle of a triangle is 120 degree and one of the interior opposite angles is 20 degree. Find the other two angles of the triangle.
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Hi there !!
We know that :
Exterior angle of a triangle = sum of the 2 interior opposite angles
Here in this case :
Exterior angle = 120°
Also , we are given one of the opposite interior angles as 20°
Let the unknown other interior opposite angle be x
x + 20° = 120°
x = 120 - 20 = 100°
So ,we get the interior opposite angles as 20° and 100°
=========================
We know that
sum of all angles of a triangle = 180°
Let the third unknown angle be y
y° + 20° + 100° = 180°
y° = 180 - 120
= 60°
So the angles of the Δ are :
60° , 100 ° , 20°
We know that :
Exterior angle of a triangle = sum of the 2 interior opposite angles
Here in this case :
Exterior angle = 120°
Also , we are given one of the opposite interior angles as 20°
Let the unknown other interior opposite angle be x
x + 20° = 120°
x = 120 - 20 = 100°
So ,we get the interior opposite angles as 20° and 100°
=========================
We know that
sum of all angles of a triangle = 180°
Let the third unknown angle be y
y° + 20° + 100° = 180°
y° = 180 - 120
= 60°
So the angles of the Δ are :
60° , 100 ° , 20°
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