an exterior angle of a triangle measure 110 degree and its interior opposite angle are in the ratio 2 ratio 3 find all the angle of the triangle
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Answer:
Let the given interior opposite angles be (2x) ° and (3x) °
We know that an exterior angle of a triangle is equal to the sum of its interior opposite angles.
∴ 2x+3x=110 °
5x=110
x=110/5=22
∴ ∠A=2x=2=2×22=44°
∠B=3x=3×22=66 °
But ∠A+∠B+∠C=180 °
44 ° +66° +∠C=180 °
110+∠C=180 °
∠C=180°−110°
∠C=70°
∠A=44 ° , ∠B=66 ° , ∠C=70 °
Answered by
0
Answer:
Let the given interior opposite angles be (2x) ° and (3x) °
We know that an exterior angle of a triangle is equal to the sum of its interior opposite angles.
∴ 2x+3x=110 °
5x=110
x=110/5=22
∴ ∠A=2x=2=2×22=44°
∠B=3x=3×22=66 °
But ∠A+∠B+∠C=180 °
44 ° +66° +∠C=180 °
110+∠C=180 °
∠C=180°−110°
∠C=70°
∠A=44 ° , ∠B=66 ° , ∠C=70 °
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