An exterior angle of a triangle measures 110° and one of its interior opposite angle is 70° Find the other interior opposite angle.
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Let the given interior opposite angles be (2x)
o
and (3x)
o
We know that an exterior angle of a triangle is equal to the sum of its interior opposite angles.
∴ 2x+3x=110
o
5x=110
x=110/5=22
∴ ∠A=2x=2=2×22=44
o
∠B=3x=3×22=66
o
But ∠A+∠B+∠C=180
o
44
o
+66
o
+∠C=180
o
110+∠C=180
o
∠C=180−110
∠C=70
o
∠A=44
o
, ∠B=66
o
, ∠C=70
o
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