An exterior angle of an triangle is 110 degree and one of its interior opposite angle is 45 degree then find other interior opposite angles
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- in ∆ABC the ext. angle=110°
Property:ext.angle= sum of two int. opposite angles
45°+angle A = 110°
angle A = 110°- 45° = 65°
for angle C
Property: sum of all the three angles of a ∆are = 180°
angle A + angle B + angle C = 180°
65° + 45°+ angle C = 180°
angle C= 180°- (65° + 45°)
angle C=180° - 110°
angle C=70°
hope this would be helpful.....
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