An external force of 10 N acts normally on a square area of each side 50 cm. The stress produced in equilibrium state is
Please can anyone solve this sum! It's really urgent
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lenth of side of square= 50 cm
=50/100 m
= 0.5 m
Force= 10N
STRESS= FORCE/AREA =10 /(0.5)(0.5)
=1000/25
=40 Pa
elena18:
thank you so much!!
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