Question

An eye kept at a depth 'h' inside water having refractive index 'μ' and is viewing outside. The radius of circle through which the outer objects can be seen, will be

Answer 1

Answer:

Explanation:

h/√u^2-1

h/u

h/√u^2+1

(√u^2-1/u)h

Answer 2

Answer:

The answer is given in the attachment, comment if it is still not clear

Also i have given the answer by supposing you know basic geometr.

Adios